NECO FURTHER MATHEMATICS EXPO

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F/Maths Obj:
1EBDCAACBD
11DEAECBECBD
21DDBDEEBEEB
31ACAADEBCED

41ABECBBDEAA

====6a)
greatest height(H)= (U^2 sin^2 tita)/2g
=956^2 sin ^2 (36)) / 2(10)
=(3136 * 0.5878 ^2)/20 =1083.516/20
=54.196
=54.18
6b)
horizontal range(R)=( U^2 sin2 tita) /g
=(56^2 sin 2(36) )/10 =(3136* sin 72)/10
=(3136* 0.9511)/10
=2982.6496/10
=298.26495
=298.26m
6c)
time of flight
=2sin tita/ g
=(2*56 sin 36) / 10
=112* 0.5878
=65.8336/10= 6.5834
(No8)
TABULATE
class interval;41-50,51-60,61-70,81-
90,91-100
Boundaries;40.5-50.5,50.5-60.5
,60.5-70.5,70.5-80.5,80.5-90.5,90.5-100.5
frequency;7,10,13,9,6,5=50
mode=L1 (D1/D1 D2)C
L1=60.5
D1=13-10=3
D2=13-9=4
C=10
mode=60.5 (3/3 4)10
=60.5 30/7
=60.5 4.286
=64.786
=64.8
median=L1 [(n/2-Efb)/fm]C
L1=60.5,N=50,Efb=7 10=17
fm=13,C=10
median=60.5 [(50/2-17)/13]*10
=60.5 (8/13)10
=60.5 80/13
=60.5 6.15
=66.65
9a)
matrices
A=
(34 2)
(1 -5 3)
(2 3 1)
|A|
=3|-5 3|-4|1 3| 2|1 -5|
|3 1| |2 1| |2 3|
=3(-5-9)-4(1-6) 2(3 10)
=-42 20 26
|A|=4
A^c=
(-14 5 13)
(2 -1 -1)
(22 -7 -19)
A^adj=
(-14 2 22)
(5 -1 -7)
(13 -1 -19)
A^-1=1/|A|
A^adj=
1/4(-14 2 22)
(5 -1 -7)
(13 -1 -19)
A^-1=
(-7/2 1/2 11/2)
(5/4 -1/4 -7/4)
(3/4 -1/4 -19/4)
9b)
(3 4 2) (x)=(4)
(1 -5 3) (y)=(-1)
(2 3 1) (z)=(3)
A B=C
B=A^-1*C
(x)=(-7/2 1/2 11/2)(4)
(y)=(5/4 -1/4 -7/4)(-1)
(z)=(13/4 -1/4 -19/4)(3)
=(-14 -1/2 33/2)
(5 1/4 -21/4)
(13 1/4 -57/4)
(x)=(2)
(y)=(0)
(z)=(-1)
therefore x=2,y=0,z=-1
(13)
Draw the diagram
frictional force Fr=mg sin tita
=5.6* 9.8* 0.5878
=32.26N Reaction R= mgcos tita
=5.6 * 9.8 cos^2 36
56* 9.8 * 0.8090
=44.40N
(a)
the force parallel to the plane Fr==32.26N
(b)
from Fr= UR
=0.45* 44.40
=19.98N
15a)
capital demand=N12,000* N120
=N5,040,000
total purchasing cost
=N140*12,000 =N1,680,000
holding cost amount =20%
=20/100 * N5,040,000
=N1,008,000
Economic order= N1,680,000 exam guruz
N1,008,000 =N2688000
ii)
total value cost per n annum
=N268800/12,000
=N224
15b)
mean x=74
s.d=15
i)
Pr(x>85)=x- xbar/ sigma
=85-74 /15
=11/15 =0.73
=0.2673
ii)
Pr(x<62)=(62-74)/15exam guru
=-12/15=-0.8
=0.2881
iii)
Pr(62 =0.5-.2673 0.5- 0.2881
=0.4446
======COMPLETED=====
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